0=x^2+42-12

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Solution for 0=x^2+42-12 equation: 



0=x^2+42-12

We move all terms to the left:

0-(x^2+42-12)=0

We add all the numbers together, and all the variables

-(x^2+42-12)=0

We get rid of parentheses

-x^2-42+12=0

We add all the numbers together, and all the variables

-1x^2-30=0

a = -1; b = 0; c = -30;
Δ = b2-4ac
Δ = 02-4·(-1)·(-30)
Δ = -120
Delta is less than zero, so there is no solution for the equation

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